3[z-2]=7z+1

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Solution for 3[z-2]=7z+1 equation:


Simplifying
3[z + -2] = 7z + 1

Reorder the terms:
3[-2 + z] = 7z + 1
[-2 * 3 + z * 3] = 7z + 1
[-6 + 3z] = 7z + 1

Reorder the terms:
-6 + 3z = 1 + 7z

Solving
-6 + 3z = 1 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-6 + 3z + -7z = 1 + 7z + -7z

Combine like terms: 3z + -7z = -4z
-6 + -4z = 1 + 7z + -7z

Combine like terms: 7z + -7z = 0
-6 + -4z = 1 + 0
-6 + -4z = 1

Add '6' to each side of the equation.
-6 + 6 + -4z = 1 + 6

Combine like terms: -6 + 6 = 0
0 + -4z = 1 + 6
-4z = 1 + 6

Combine like terms: 1 + 6 = 7
-4z = 7

Divide each side by '-4'.
z = -1.75

Simplifying
z = -1.75

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